README_EN.md

833. Find And Replace in String

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Description

To some string S, we will perform some replacement operations that replace groups of letters with new ones (not necessarily the same size).

Each replacement operation has 3 parameters: a starting index i, a source word x and a target word y.  The rule is that if x starts at position i in the original string S, then we will replace that occurrence of x with y.  If not, we do nothing.

For example, if we have S = "abcd" and we have some replacement operation i = 2, x = "cd", y = "ffff", then because "cd" starts at position 2 in the original string S, we will replace it with "ffff".

Using another example on S = "abcd", if we have both the replacement operation i = 0, x = "ab", y = "eee", as well as another replacement operation i = 2, x = "ec", y = "ffff", this second operation does nothing because in the original string S[2] = 'c', which doesn't match x[0] = 'e'.

All these operations occur simultaneously.  It's guaranteed that there won't be any overlap in replacement: for example, S = "abc", indexes = [0, 1], sources = ["ab","bc"] is not a valid test case.

Example 1:

Input: S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee","ffff"]

Output: "eeebffff"

Explanation: "a" starts at index 0 in S, so it's replaced by "eee".

"cd" starts at index 2 in S, so it's replaced by "ffff".

Example 2:

Input: S = "abcd", indexes = [0,2], sources = ["ab","ec"], targets = ["eee","ffff"]

Output: "eeecd"

Explanation: "ab" starts at index 0 in S, so it's replaced by "eee". 

"ec" doesn't starts at index 2 in the original S, so we do nothing.

Notes:

<li><code>0 &lt;=&nbsp;indexes.length =&nbsp;sources.length =&nbsp;targets.length &lt;= 100</code></li>

<li><code>0&nbsp;&lt;&nbsp;indexes[i]&nbsp;&lt; S.length &lt;= 1000</code></li>

<li>All characters in given inputs are lowercase letters.</li>

 

Solutions

Python3

Java

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