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Description

We are given a linked list with head as the first node.  Let's number the nodes in the list: node_1, node_2, node_3, ... etc.

Each node may have a next larger value: for node_inext_larger(node_i) is the node_j.val such that j > i, node_j.val > node_i.val, and j is the smallest possible choice.  If such a j does not exist, the next larger value is 0.

Return an array of integers answer, where answer[i] = next_larger(node_{i+1}).

Note that in the example inputs (not outputs) below, arrays such as [2,1,5] represent the serialization of a linked list with a head node value of 2, second node value of 1, and third node value of 5.

 

Example 1:

Input: [2,1,5]

Output: [5,5,0]

Example 2:

Input: [2,7,4,3,5]

Output: [7,0,5,5,0]

Example 3:

Input: [1,7,5,1,9,2,5,1]

Output: [7,9,9,9,0,5,0,0]

 

Note:

    <li><code><span>1 &lt;= node.val&nbsp;&lt;= 10^9</span></code><span>&nbsp;for each node in the linked list.</span></li>
    
    <li>The given list has length in the range <code>[0, 10000]</code>.</li>
    

Solutions

Python3

Java

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