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107.二叉树的层次遍历-ii.cpp
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66 lines (59 loc) · 1.65 KB
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/*
* @lc app=leetcode.cn id=107 lang=cpp
*
* [107] 二叉树的层次遍历 II
*/
// @lc code=start
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrderBottom(TreeNode* root) {
vector<vector<int>>& result = *new vector<vector<int>>;
queue<TreeNode*> que; // 队列。
if (root)
{
que.push(root);
}
else
{
return result;
}
int sum = que.size(); // 记录每一层的指针个数以便从队列取出。
while (sum != 0)
{
vector<int> buffer;
for (int i = 0; i < sum; i++)
{
// 不用判断 que.front() 为 null 因为加入队列时就限制了。
buffer.push_back(que.front()->val);
// 只有当左右指针不为 null 时才加入队列。
if (que.front()->left)
{
que.push(que.front()->left);
}
if (que.front()->right)
{
que.push(que.front()->right);
}
que.pop();
}
sum = que.size();
result.push_back(buffer);
}
// 先顺序层次遍历再按层交换
for (int i = 0; i < result.size() / 2; i++)
{
swap(result.at(i), result.at(result.size() - i - 1));
}
return result;
}
};
// @lc code=end