0008._string_to_integer_(atoi).md

8. String to Integer (atoi)

难度: Medium

刷题内容

原题连接

• https://leetcode.com/problems/string-to-integer-atoi/

内容描述

Implement atoi which converts a string to an integer.

The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.

The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.

If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.

If no valid conversion could be performed, a zero value is returned.

Note:

Only the space character ' ' is considered as whitespace character.
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. If the numerical value is out of the range of representable values, INT_MAX (231 − 1) or INT_MIN (−231) is returned.
Example 1:

Input: "42"
Output: 42
Example 2:

Input: "   -42"
Output: -42
Explanation: The first non-whitespace character is '-', which is the minus sign.
             Then take as many numerical digits as possible, which gets 42.
Example 3:

Input: "4193 with words"
Output: 4193
Explanation: Conversion stops at digit '3' as the next character is not a numerical digit.
Example 4:

Input: "words and 987"
Output: 0
Explanation: The first non-whitespace character is 'w', which is not a numerical 
             digit or a +/- sign. Therefore no valid conversion could be performed.
Example 5:

Input: "-91283472332"
Output: -2147483648
Explanation: The number "-91283472332" is out of the range of a 32-bit signed integer.
             Thefore INT_MIN (−231) is returned.

解题方案

思路 1 - 时间复杂度: O(N)- 空间复杂度: O(1)******

需要考虑比较多的边界条件&特殊情况

1. 首先输入可能会有空格，所以先去掉空格
2. 去掉空格后要考虑空字符串情况
3. 字符串首位可能会有正负号，要考虑
4. 开始转换成数字，题目说只要遇到非数字就可以break了
5. 结果太大或者太小超过int限制就要返回特定数字 2147483647 或者 -2147483648
6. 根据之前的正负号结果返回对应数值

class Solution(object):
    def myAtoi(self, str):
        """
        :type str: str
        :rtype: int
        """
        str = str.strip()
        strNum = 0
        if len(str) == 0:
            return strNum

        positive = True
        if str[0] == '+' or str[0] == '-':
            if str[0] == '-':
                positive = False
            str = str[1:]

        for char in str:
            if char >= '0' and char <= '9':
                strNum = strNum * 10 + ord(char) - ord('0')
            if char < '0' or char > '9':
                break

        if strNum > 2147483647:
            if positive == False:
                return -2147483648
            else:
                return 2147483647
        if not positive:
            strNum = 0 - strNum
        return strNum