难度: Easy
原题连接
内容描述
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its depth = 3.
思路 1 - 时间复杂度: O(N)- 空间复杂度: O(1)******
简单题,但是这道题跟leetcode111不一样,这道题没有特殊情况,所以一行就够了
class Solution(object):
def maxDepth(self, root):
"""
:type root: TreeNode
:rtype: int
"""
return 1 + max(map(self.maxDepth, (root.left, root.right))) if root else 0