难度: Easy
原题连接
内容描述
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Note: A leaf is a node with no children.
Example:
Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
思路 1 - 时间复杂度: O(N)- 空间复杂度: O(1)******
Easy
递归
class Solution(object):
def hasPathSum(self, root, sum):
"""
:type root: TreeNode
:type sum: int
:rtype: bool
"""
if not root:
return False
if root.left or root.right:
return self.hasPathSum(root.left, sum-root.val) or self.hasPathSum(root.right, sum-root.val)
else:
return root.val == sum