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CheezItMan
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May 12, 2019
CheezItMan
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You have a pretty good solution here, nice use of the hash table. Well done.
| if array1 == nil || array2 == nil | ||
| return [] | ||
| end | ||
| if array1.length < array2.length |
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It doesn't really matter which array you put into the hash table since you have to go through both. So this if statement is a bit wasted.
| # Time complexity: ? | ||
| # Space complexity: ? | ||
| # Time complexity: O(n + m) where n is the number of items of one array and m is the number of items in the other | ||
| # Space complexity: O(n) |
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