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homework done
Update main.kt
Antol
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Feb 24, 2022
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| // Вернуть количество клментов из выбранного города | ||
| fun Shop.countCustomersFrom(city: City): Int = 0 | ||
| fun Shop.countCustomersFrom(city: City): Int = customers.filter { it.city==city }.toSet().size |
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Хорошо, но можно просто customers.count{ it.city == city }
| // Вернуть словарь в котором названия городов являются ключами, а значениями - сет клиентов, проживающих в этом городе | ||
| fun Shop.groupCustomersByCity(): Map<String, Set<Customer>> = mapOf() | ||
| fun Shop.groupCustomersByCity(): Map<String, Set<Customer>> { | ||
| val cities = getCitiesCustomersAreFrom() |
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Интересно, не подумал что можно другие функцию использовать, но не очень по оптимальности решение получается, много лишнего. Так проще
customers.groupBy { it.city.title }.mapValues { it.value.toSet() }
| // Вернуть сет клиентов, у которых не доставленных заказов больше чем заказанных | ||
| fun Shop.getCustomersWithMoreUndeliveredOrdersThanDelivered(): Set<Customer> = setOf() | ||
| fun Shop.getCustomersWithMoreUndeliveredOrdersThanDelivered(): Set<Customer> = | ||
| customers.filter{ (it.orders.filter { !it.isDelivered }.size) > (it.orders.filter { it.isDelivered }.size)}.toSet() |
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Ок. Можно было еще через partition, чуть читабельнее (для тех кто знаком с такой функцией конечно)
customers.filter {
val (del, undel) = it.orders.partition { it.isDelivered }
undel.count() > del.count()
}.toSet()
| fun Customer.getMostExpensiveDeliveredProduct(): Product? { | ||
| val products = orders.filter{it.isDelivered}.flatMap {it.products} | ||
| val maxPrice = products.maxOfOrNull { it.price } | ||
| return products.find { it.price==maxPrice } |
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Можно без создания дополнительных переменных
orders.filter { it.isDelivered }.flatMap { it.products }.maxByOrNull { it.price }
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homework done