Make getNodeForName method match entire name

[austin-hoover]

Currently getNodeForName(name) returns node if node.getName().find(name) == 0. This throws an error if there is another node with the same prefix. For example:

names = ["QH10", "QH10A", "QH10B"]
for name in names:
    print(name, name.find("QH10"))

QH10 0
QH10A 0
QH10B 0

Is this intended behavior?

[shishlo]

I agree that
if node.getName().find(name) == 0:
should be replaced with
if node.getName() == name:

The same also should be done inside (line 140)
def getNodesForName(self, name):

The error for
def getNodeForName(self, name):
should tell that there are several AccNodes with the same name (it could happen in TEAPOT lattices), and user should be aware about that and should use "getNodesForName" method.