Fifth power #63
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Fifth power #63
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Digit fifth powers
d2 = 0
d3 = 0
d4 = 0
d5 = 0
numbers = []
soma = 0
while True:
num = (d1**5) + (d2**5) + (d3**5) + (d4**5) + (d5**5)
if str(num) == str(d1) + str(d2) + str(d3) + str(d4) + str(d5):
numbers.append(num)
d5 += 1
if d5 >= 9:
d5 = 0
d4 += 1
if d4 >= 9:
d4 = 0
d3 += 1
if d3 >= 9:
d3 = 0
d2 += 1
if d2 >= 9:
d2 = 0
d1 += 1
if d1 >= 9: break
for e in numbers:
soma += e
print(e)
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Hey, thank you for your contribution! Please check the contribution guideline and modify your PR accordingly. Thanks! |
AdarshRise
added
bug
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