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lab03, Recursive and cycle functions #3
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RostislavPorohnya
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,42 @@ | ||
| public class Main { | ||
| public static void main(String[] args) { | ||
| int n = 4; | ||
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| factorial fact = new factorial(); | ||
| int res1 = fact.recursionExecute(n); | ||
| System.out.println("Factorial recursive n: " + n); | ||
| System.out.println("Factorial recursive execute: " + res1); | ||
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| int res2 = fact.cycleExecute(n); | ||
| System.out.println("Factorial cycle n: " + n); | ||
| System.out.println("Factorial cycle execute: " + res2); | ||
| assert res1 == res2 : "different values"; | ||
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| fibonacci fib = new fibonacci(); | ||
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| res1 = fib.recursionExecute(n); | ||
| System.out.println("Fibonacci recursive n: " + n); | ||
| System.out.println("Fibonacci recursive execute: " + res1); | ||
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| res2 = fib.cycleExecute(n); | ||
| System.out.println("Fibonacci cycle n: " + n); | ||
| System.out.println("Fibonacci cycle execute: " + res2); | ||
| assert res1 == res2 : "different values"; | ||
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| int number = 233151; | ||
| digitsSum digitSum = new digitsSum(); | ||
| res1 = digitSum.execute(number); | ||
| System.out.println("Digits sum number: " + number); | ||
| System.out.println("Digits sum recursive execute: " + res1); | ||
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| int x = 5; | ||
| int y = 2; | ||
| sum sum = new sum(); | ||
| res1 = sum.execute(x,y); | ||
| System.out.println("Sum without arithmetic operations x: " + x + ", y: " + y); | ||
| System.out.println("Sum without arithmetic operations execute: " + res1); | ||
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| } | ||
| } |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,9 @@ | ||
| public class digitsSum { | ||
| int execute(int number){ | ||
| if (number == 0){ | ||
| return 0; | ||
| } | ||
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| return (number % 10) + execute(number/10); | ||
| } | ||
| } |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,15 @@ | ||
| public class factorial { | ||
| int recursionExecute(int n){ | ||
| if (n < 1) return 1; | ||
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| return n * recursionExecute(n - 1); | ||
| } | ||
| int cycleExecute(int n){ | ||
| int res = 1; | ||
| for(int i = 1; i <= n; i++){ | ||
| res *= i; | ||
| } | ||
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| return res; | ||
| } | ||
| } |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,22 @@ | ||
| public class fibonacci { | ||
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| int recursionExecute(int n){ | ||
| if (n <= 1) return n; | ||
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| int curr = recursionExecute(n - 1); | ||
| int prev = recursionExecute(n - 2); | ||
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| return curr + prev; | ||
| } | ||
| int cycleExecute(int n){ | ||
| int prev = 0; | ||
| int curr = 1; | ||
| for (int i = 0; i <= n; i++){ | ||
| int temp = curr; | ||
| curr = prev + curr; | ||
| prev = temp; | ||
| } | ||
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| return curr; | ||
| } | ||
| } |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,7 @@ | ||
| public class sum { | ||
| public int execute(int x, int y){ | ||
| if (y == 0) return x; | ||
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| return execute(x ^ y, (x & y) << 1); | ||
| } | ||
| } | ||
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і тут так само. Зможете мені пояснити на пальцях як цее працює? з усіма зсувами і логічними функціями?
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Я використовую
x ^ yщоб скласти ці два значення, потім складаю це значення зx & y << 1- для того щоб врахувати "перенесені біти" допокиx & y << 1(перенесені біти) не будуть дорівнювати 0 (перенесених бітів немає)