Eigenvalues, eigenvectors, and eigenspaces of linear endomaps#1765
Eigenvalues, eigenvectors, and eigenspaces of linear endomaps#1765lowasser wants to merge 47 commits intoUniMath:masterfrom
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…math into linear-transformations
Co-authored-by: Fredrik Bakke <fredrbak@gmail.com>
…math into linear-transformations
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I'm not familiar enough with the subject of spectral theory to make an informed decision on whether eigenvalues and eigenvectors should go into that namespace. Could you please write an introduction to this namespace meriting the inclusion of eigenvalues and eigenvectors? Something akin to the introduction of |
src/spectral-theory/eigenspaces-linear-endomaps-vector-spaces.lagda.md
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...ral-theory/eigenvalues-eigenelements-linear-endomaps-left-modules-commutative-rings.lagda.md
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Co-authored-by: Fredrik Bakke <fredrbak@gmail.com>
Done. |
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(tl;dr: spectral theory is the field that studies eigenvectors, eigenvalues, and their generalizations) |
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Have you considered defining the
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src/spectral-theory/eigenmodules-linear-endomaps-left-modules-commutative-rings.lagda.md
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Co-authored-by: Fredrik Bakke <fredrbak@gmail.com>
I'm certainly on board with this part;
I'm not sure I see yet how to define these things for arbitrary spaces (largely because the notion of "nonzero" generally requires a space-specific notion of apartness which I don't want to demand from these spaces yet) |
I suspected so, but I was hoping the hypothesis on Heyting fields would be enough to characterize nonzero vectors. Maybe using duality (e.g. a vector |
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Defining nonzero vectors is the important one, and it might be plausible to define a nonzero vector as If there is a viable definition here, I don't feel the need for it here; I don't really see where "zero is an eigenvalue for every vector" is a problem. Certainly I think things line up better if we keep the definition to "c is an eigenvalue with eigenvector v if f v - c * v = 0`. |
I don't know much about spectral theory in arbitrary commutative rings but, for vector spaces, the fact that eigenvectors must be nonzero always seemed quite relevant.
That's not it. The problem is "the zero vector is an eigenvector for all values", or, put it another way, "any value is an eigenvalue for the zero vector". So I thing the term eigen is not correctly applied. |
It seemed like an appropriate point to inaugurate a
spectral-theorymodule.Builds on #1764 .