chore(deps-dev): bump mimic from 1.12.0 to 2.0.0

[dependabot]

Bumps mimic from 1.12.0 to 2.0.0.

Release notes

Sourced from mimic's releases.

Mimic 2.0.0

What's Changed

• feat!: change expect/3,4 to not call original once fulfilled by @​edgurgel in edgurgel/mimic#98

Breaking changes

The code below would call the original Calculator.add/2 when all expectations were fulfilled.

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
assert Calculator.add(1, 1) == :expected1
assert Calculator.add(1, 1) == :expected2
assert Calculator.add(1, 1) == 2

Now with Mimic 2 this will raise:

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
assert Calculator.add(1, 1) == :expected1
assert Calculator.add(1, 1) == :expected2
Calculator.add(1, 1)
Will raise error because more than 2 calls to Calculator.add were made and there is no stub
** (Mimic.UnexpectedCallError) Calculator.add/2 called in process #PID<.*> but expectations are already fulfilled

If there is a stub the stub will be called instead. This behaviour is the same as before.

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
 |> stub(:add, fn _, _ -> :stub end)
assert Calculator.add(1, 1) == :expected1
assert Calculator.add(1, 1) == :expected2
assert Calculator.add(1, 1) == :stub

Which means that if someone wants to keep the original behaviour on Mimic 1.* just do the following:

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
</tr></table> 

... (truncated)

Changelog

Sourced from mimic's changelog.

2.0.0 (2025-07-13)

Breaking changes

The code below would call the original Calculator.add/2 when all expectations were fulfilled.

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
assert Calculator.add(1, 1) == :expected1
assert Calculator.add(1, 1) == :expected2
assert Calculator.add(1, 1) == 2

Now with Mimic 2 this will raise:

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
assert Calculator.add(1, 1) == :expected1
assert Calculator.add(1, 1) == :expected2
Calculator.add(1, 1)
Will raise error because more than 2 calls to Calculator.add were made and there is no stub
** (Mimic.UnexpectedCallError) Calculator.add/2 called in process #PID<.*> but expectations are already fulfilled

If there is a stub the stub will be called instead. This behaviour is the same as before.

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
 |> stub(:add, fn _, _ -> :stub end)
assert Calculator.add(1, 1) == :expected1
assert Calculator.add(1, 1) == :expected2
assert Calculator.add(1, 1) == :stub

Which means that if someone wants to keep the original behaviour on Mimic 1.* just do the following:

 Calculator
 |> expect(:add, fn _, _ -> :expected1 end)
 |> expect(:add, fn _, _ -> :expected2 end)
 |> stub(:add, fn x, y -> call_original(Calculator, :add, [x, y]) end)
</tr></table> 

... (truncated)

Commits

• fee2662 feat!: change expect/3,4 to not call original once fulfilled (#98)
• See full diff in compare view

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