Xiang Wang @ 2016-05-26 15:30:51
(?!...)
后续不能出现...\d数字\D非数字\s空白字符\S非空白字符\w单词字符\W非单词字符(a|bc|d)a或者bc或者c[a-z]* 小写字母- 是否是贪婪模式: 在匹配后面加上?, 比如
*? +? ?? {4, 6}? (?P<name>...)
或者匹配的时候就能用
m = re.match(r'(?P<index>\d+)word(?P=index)', '123word123') # 用\1也可以
匹配楚Name, 之后可以获取
m = re.match(r'(?P<name>.*)', 'name')
print(m.group('name'))
print(m.end('name')) # TODO
Module Contents 模块内容 官网
- re.compile
re.compile(r'(?P<id>\d+)we').match('123we').group('id')
- re.A
- re.ASCII
- ...
- re.sub(pattern, repl, string, count=0, flags=0)
re.sub(r'(00)*$', '', '100000') # 把匹配到的数据变成空
测试代码
Return the string obtained by replacing the leftmost non-overlapping occurences of pattern in string by the replacement repl. The repl can be a function.
- 每次匹配把结果里面的数据拿出来
re.sub('a(\d)b', r'\1', 'a4bcdaba2b') - 替换手机号码
re.sub('(\d*)(\d{4})(\d{3})', r"\1****\3", "7982660")
- 使用函数来替换
>>> def dashrepl(matchobj):
... if matchobj.group(0) == '-': return ' '
... else: return '-'
>>> re.sub('-{1,2}', dashrepl, 'pro----gram-files')
'pro--gram files'
- ...
>>> def repl(m):
... inner_word = list(m.group(2))
... random.shuffle(inner_word)
... return m.group(1) + "".join(inner_word) + m.group(3)
>>> text = "Professor Abdolmalek, please report your absences promptly."
>>> re.sub(r"(\w)(\w+)(\w)", repl, text)
'Poefsrosr Aealmlobdk, pslaee reorpt your abnseces plmrptoy.'
>>> re.sub(r"(\w)(\w+)(\w)", repl, text)
'Pofsroser Aodlambelk, plasee reoprt yuor asnebces potlmrpy.'
- 找到字符串里面符合规则的字符串
a = re.compile(r'^数据更新时间：(?P<time>[0-9: -]*)').match('数据更新时间：2016-05-25 16:00:00')
print(a.groupdict())
- 把字符串里面符合规则的字符进行替换
re.splite(r'\.0*', text)
- 删除字符串里面符合规则的字符串