fixing the logic of calculating the sum of even numbers

[Kneysh]

Fixed the logic of calculating the sum of even numbers

Question : Calculate the sum of even numbers up to a given number n

In the previous solution it was just counting the total even numbers up to a given number n as it was just adding 1 to the variable sum_even. But I changed it and now it adds the current even number to the the variable sum_even which holds the value of the summation of the previous even numbers. Also now the value of 'n' comes from the user.

previous code:

`n = 4
sum_even = 0

for i in range(1, n+1):
if i%2 == 0:
sum_even += 1

print("Sum of the even numbers: , ", sum_even)`

current code:

`n = int(input("Enter the number to add up to: ")) # takes the limit from user
sum_even = 0

for i in range(1, n+1):
if i%2 == 0:
sum_even += i # adds the current even number to the sum of the previous ones

print(f"Sum of the even numbers upto {n} is {sum_even}")`