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add enumerating all submasks #29

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8 changes: 8 additions & 0 deletions README.md
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Expand Up @@ -208,6 +208,14 @@ x = a ^ b ^ x;
```
~(n^m)&(n^m)+1 // returns 2^x where x is the position of the common bit (0 based)
```
**Enumerate all submasks of n**
```
int s = n;
while (s > 0) {
// you can use s here
s = (s-1) & n;
}
```
## Floats

These are techniques inspired by the [fast inverse square root method.](https://en.wikipedia.org/wiki/Fast_inverse_square_root) Most of these
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