Solution

[andriynavr07]

No description provided.

[mateacademy-ai-mentor]

Review Summary

Your solution is approved because it correctly fulfills the task requirements for count_occurrences. The function signature matches exactly (def count_occurrences(phrase: str, letter: str) -> int), and your implementation properly counts how many times a given letter appears in phrase. You also implemented case-insensitive comparison by lowercasing both the current character and the target letter, so examples like "letter", "t" → 2 and "ABC", "a" → 1 behave as required.

There are no critical or blocking issues: the function is correct, robust for the described inputs, and aligned with the expected behavior. One minor improvement you could consider (not required) is using built-in string methods, for example phrase.lower().count(letter.lower()), to make the code a bit more concise and idiomatic. Overall, well done implementing the core logic cleanly and meeting all the specified requirements.

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[Copilot]

Pull request overview

Implements the previously stubbed count_occurrences function so it returns a case-insensitive count of a given letter in a phrase, matching the project’s task requirements and existing tests.

Changes:

• Replaced the placeholder pass implementation with working counting logic.
• Ensured comparisons are case-insensitive by normalizing characters during comparison.
• Returned the computed count instead of leaving the function unimplemented.

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