Is the flattenig of Jupiter taken into account in the polar projection grid?

[CorentinLouis]

I am opening this issue just to be sure that there isn't an issue in the polar projection grid.

when we are projecting trajectory (or footprints of satellite) in polar projection using python, you need to be careful:
if you take into account the flattening of the planet in the projection of Juno path (or satellite footprint), and that you then just use the matplotlib.pyplot polar plot method, the grid won't take into account the flattening of the planet, and your projection will be wrong.

Looking at the routine here :
https://github.com/mattkjames7/JupiterMag/blob/main/JupiterMag/TraceField.py

line 702:
ax = fig.subplot2grid((maps[1],maps[0]),(maps[3],maps[2]),projection='polar')

I don't think the flattening of Jupiter is taken into account for the projected grid...

Am I right?

[mattkjames7]

Hi Corentin,
Thanks for using our code.
Currently that plotting function only plots the footprints on a colatitude-longitude grid in a polar projection (i.e. the radial axis of the plot is simply 90-latitude), I was planning on adding a second projection which would use the x and y coordinates of the footprints (in SIII) instead. Would this be more like what you are after? Or are you concerned with the actual footprint coordinates themselves being wrong? (they are traced to an oblate spheroid rather than a sphere)
Cheers,
Matt.