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norrise120
reviewed
Aug 15, 2019
| const calculateAverage = function calculateAverage(grades) { | ||
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| let total = 0; | ||
| for (let i = 0; i < grades.length; i++) { |
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What happens if grades is null? Does a statement need to be added for this edge case?
| total += grades[i]; | ||
| } | ||
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| let avg = total / grades.length; |
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What should be returned if there are no grades? I think you would get undefined here if grades is an empty array.
laneia
reviewed
Aug 15, 2019
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| const calculateAverage = function calculateAverage(grades) { | |||
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Consider refactoring into an arrow function
jillirami
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Aug 15, 2019
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| const calculateAverage = function calculateAverage(grades) { | |||
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Suggested change
| if (grades == null || grades == undefined) { | |
| return "No Grades Provided"; | |
| } |
bonara
reviewed
Aug 15, 2019
| @@ -0,0 +1,14 @@ | |||
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| const calculateAverage = function calculateAverage(grades) { | ||
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| let total = 0; | ||
| for (let i = 0; i < grades.length; i++) { |
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forEach loop might be better for an array
| let avg = total / grades.length; | ||
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| return avg; | ||
| }; |
sjscotton
reviewed
Aug 15, 2019
| const calculateAverage = function calculateAverage(grades) { | ||
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| let total = 0; | ||
| for (let i = 0; i < grades.length; i++) { |
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Maybe consider using a for of loop:
for (grade of grades) {
}
| total += grades[i]; | ||
| } | ||
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| let avg = total / grades.length; |
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Suggested change
| let avg = total / grades.length; | |
| const avg = total / grades.length; |
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This method will calculate the average of an array of grades.