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请问：如何进行复合查询？比如找到CastShape和CollideShape的并集？或者两次不同的CastShape的并集？(Translation: Question: How do I perform a compound query? For example, how do I find the union of CastShape and CollideShape? Or the union of two different CastShapes?) #2099
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[-]请问：如何进行复合查询？比如找到CastShape和CollideShape的并集？或者两次不同的CastShape的并集？[/-][+]请问：如何进行复合查询？比如找到CastShape和CollideShape的并集？或者两次不同的CastShape的并集？(Translation: Question: How do I perform a compound query? For example, how do I find the union of CastShape and CollideShape? Or the union of two different CastShapes?)[/+]on Aug 22, 2026 The automatic translation may be a bit weird so I'm not really sure what you're asking.
If you're asking how to do multiple queries in a single call: Just call the
CollideShape/CastShapefunction multiple times. I've tried creating an interface that processes multiple queries at the same time in the past, but it wasn't faster.If you're asking how to test a collection of shapes against the world / other shapes then combine the query shapes into a
StaticCompoundShapeorMutableCompoundShape.If you're asking how to do a
CollideShapeand aCastShapeat the same time:CastShapeis a superset ofCollideShape. If you setShapeCastSettings::mReturnDeepestPoint = truethenCastShapewill return the same information asCollideShapewhen a hit withShapeCastResult::mFraction == 0is returned.- Repository owner locked and limited conversation to collaborators
on Aug 22, 2026
如标题，我不知道怎么样写性能才会好，在我的场景，需要复合查询的两次查询的范围差距很大，比如可能一个范围很大，一个范围很小，甚至两次使用的shape都不一定一样
Translation: As the title suggests, I'm unsure how to write a performance-efficient query. In my scenario, the ranges of the two queries in a compound query differ significantly—for example, one range might be very large while the other is very small, and even the shapes used in the two queries might not be the same.